bash for loop doesnt print correctly

Question

I have this simple for loop

#!/bin/bash
for number in {1..10}   
    do
        echo $number
    done

but when I execute it with sh test.sh the output is

{1..10}

What is wrong?

Artur · Accepted Answer · 2018-09-29 11:28:06Z

4

You declare at the top that the script uses bash and run it with sh.

If you just type this in the command line it will work:

./name_of_the_script

Alternatively, you can call on the bash interpreter explicitly:

bash name_of_the_script

answered Sep 29, 2018 at 11:26

Artur

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2 Comments

What is the way to execute it with sh?,Thank you.

Use correct sh syntax: for i in $(seq 1 10); do echo $i done