replace element at an index of an array then reset array using for loop

Question

I want to update only 1 element in the 1d array and then start over fresh. if viewed as a matrix form I just want entries i = j to be changed.

my code so far:

import numpy as np
a = np.array([10, 20, 30, 40, 50])

for i, j in enumerate(a):
    b = a
    b[i] = j + 1
    print(b)

I want each iteration of the for loop to only change one element and keep everything else the same.

the output I want looks like this:

[11, 20, 30, 40, 50]
[10, 21, 30, 40, 50]
[10, 20, 31, 40, 50]
[10, 20, 30, 41, 50]
[10, 20, 30, 40, 51]

but I'm getting this because b is not resetting even though I am (or at lest i think) restoring the original array at the start of each loop.

[11, 20, 30, 40, 50]
[11, 21, 30, 40, 50]
[11, 21, 31, 40, 50]
[11, 21, 31, 41, 50]
[11, 21, 31, 41, 51]

any ideas where I went wrong? TIA

Replace b=a with b=a.copy()

Arihant
– Arihant

2018-09-30 03:09:38 +00:00
Commented Sep 30, 2018 at 3:09 — Arihant
– Arihant, Commented Sep 30, 2018 at 3:09

Arihant · Accepted Answer · 2018-09-30 03:13:05Z

1

Try replacing b=a with b=a.copy() b=a, will create b and point to the same memory. Whereas b=a.copy(), creates a copy of a and stores it as b in different memory location.

answered Sep 30, 2018 at 3:13

Arihant

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