Does someone have a good, fast SQL Server function that will take a string with a delimiter and return it as a table?
Thanks
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I highly recommend the articles available from sommarskog.se/arrays-in-sql.html (Arrays and Lists in SQL Server) as many various methods are discussed thoroughly.Enull– Enull2011-03-10 13:59:25 +00:00Commented Mar 10, 2011 at 13:59
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2 Answers
CREATE FUNCTION dbo.fnSplit(
@sInputList VARCHAR(8000) -- List of delimited items
, @sDelimiter VARCHAR(8000) = ',' -- delimiter that separates items
) RETURNS @List TABLE (item VARCHAR(8000))
BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
BEGIN
SELECT
@sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
@sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))
IF LEN(@sItem) > 0
INSERT INTO @List SELECT @sItem
END
IF LEN(@sInputList) > 0
INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
GO
--Test
select * from fnSplit('1,22,333,444,,5555,666', ',')
select * from fnSplit('1##22#333##444','##') --note second item has embedded #
select * from fnSplit('1 22 333 444 5555 666', ' ')
Comments
Added a bit of a twist to get the resulting items to be Integers and leveraged the NVARCHAR(MAX) capabilities of SQL 2008+
GO
/****** Object: UserDefinedFunction [dbo].[udf_fnSplit] Script Date: 05/28/2013 15:22:00 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[udf_fnSplit](
@sInputList VARCHAR(MAX) -- List of delimited items
, @sDelimiter VARCHAR(MAX) = ',' -- delimiter that separates items
) RETURNS @List TABLE (id int)
BEGIN
DECLARE @sItem VARCHAR(8000)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
BEGIN
SELECT
@sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
@sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))
IF LEN(@sItem) > 0
INSERT INTO @List SELECT CONVERT(INT,@sItem)
END
IF LEN(@sInputList) > 0
INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
