How to sort a list in python based on internal list? [duplicate]

Question

I have a list as follow:

list1 = [['10', 'John', 'python'], ['1', 'Sara', 'java'], ['3','Tom', 'C']]

and as sorted result I expect following outpt:

3 Tom C
1 Sara Java
10 John python

in fact I want to sort it base on second parameter in internal list. This code does not work:

sort1 = sorted(list1, key=lambda x: x[0][1])

Mehrdad Pedramfar · Accepted Answer · 2018-10-01 11:48:30Z

2

try this:

sort1 = sorted(list1, key=lambda x: x[1])

that [1] will be enough because it will iterate through the list and in each iteration x will be the inner list.

answered Oct 1, 2018 at 11:47

Mehrdad Pedramfar

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2 Comments

Please Add explanation.

It just needs to add reverse=True to the end to receive expected answer.