PHP put an if command in an array [duplicate]

Question

This is a bit of an odd one. I am building an array in PHP and then encoding it to JSON before I spit it out.

$arr = array (
  'reportDescription' => 
  array (
    if ($queryType == "realtime") 
    {
        'source' => 'realtime',
    }
    'reportSuiteID' => 'rbsglobretailprod',
    'dateGranularity' => $queryGran,
    'dateFrom' => $queryFrom,
    'dateTo' => $queryTo,
    'elements' => 
    array (
      0 => 
      array (
        'id' => $queryElement,
      ),
    ),
    'metrics' => 
    array (
      0 => 
      array (
        'id' => $queryMetric,
      ),
    ),
  ),
);

I am trying to get it to add a line to the array if the query type is realtime. This is what I tried but I'm not sure if it's possible to do this, and if it's not, I'm not sure how I should approach it. The error I get below suggests it may not be possible:

Parse error: syntax error, unexpected 'if' (T_IF), expecting ')'

Remove the if statement. After you declare your array add something like if ($queryType == "realtime") { $arr['source'] = 'realtime'; } — Darragh Enright
– Darragh Enright, Commented Oct 1, 2018 at 12:39

Mikey · Accepted Answer · 2018-10-01 12:39:00Z

5

You should do it as two separate calls:

$array = ['your', 'array', 'with', 'fields']
if ($queryType === 'realtime') {
    $array[] = ['source' => 'realtime'];
}

Obviously change out the values with your expected values, but that should do the job. You could also append like so if you wanted it at root level:

if ($queryType === 'realtime') {
    $array['source'] = 'realtime';
}

answered Oct 1, 2018 at 12:39

Mikey

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