how to create for loop grep in bash

Question

I'm trying to create a for loop that counts the number of keywords in each file within a directory separately.

For Example if a directory has 2 files I would like the for loop to say

foo.txt = found 4 keywords
bar.txt = found 3 keywords

So far I have written the below but its give the total number keywords from all files instead of for each separate file.

The result I get is

7 keywords founds

Instead of the desired output above

Here is what I came up with

for i in *; do egrep 'The version is out of date|Fixed in|Identified the following' /path/to/directory* | wc -l ; done

Alex Howansky · Accepted Answer · 2018-10-04 15:57:57Z

1

Just use grep's -c count option:

grep -c <pattern> /path/to/directory/*

You'll get something like:

bar.txt:2
foo.txt:1

Note this will count lines matched, not individual patterns matched. So if a pattern appears twice on a line, it will only count once.

answered Oct 4, 2018 at 15:57

Alex Howansky

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1 Comment

This is exactly what I was looking for ! Thank you !