Is it possible to use await with a parameter? for example:
const run = async () => {
getStudentDetails(await getStudentId());
}
Even if it is, it seems like it might not be the best idea. Anyone done this before?
3 Answers
Yes, you can use await expressions in every arbitrary context (where it parses) inside the async function, including as arguments to function calls. There's nothing wrong with it.
It's equivalent to
const run = async () => {
const studentId = await getStudentId();
getStudentDetails(studentId);
}
2 Comments
Explosion Pills
And as long as you are in the same calling context as the async function, e.g. this doesn't work:
async () => fnTakingCb(() => await getStudentId());
Bergi
@ExplosionPills Yes, that's not in the async function, that's in the arrow function callback.
I do it all the time. However in case if you want to pass more than one parameter to function they will be resolved sequentially. To fight that problem I wrote an util function which looks like that:
async function call(func, ...args) {
return func(...await Promise.all(args));
}
(async function() {
console.log(await call(functionToCall, delay(2000), delay(2000)));
})();
With that syntax functionToCall will be called in 2 seconds instead of 4
Comments
Yes, this will work, as you can use the await keyword everywhere where you can use an expression.
However, I'd prefer a slightly updated version of your code for better readability (and for better debugability, too):
const run = async () => {
const studentId = await getStudentId();
getStudentDetails(studentId);
}
I hope this helps 😊
awaitis good for!var pw=this.parseHex(await this.derive(password));foo(await bar1(), await bar2())? I assumebar2waits untilbar1but I'm too lazy to try and have never used that syntax