How to free an array of pointers?

Question

I've got a problem. I am trying to free an array of pointers using a loop, but it does not work. Could somebody help me with that?

This is the allocation code:

void create1(A*** a, int size)
{
    *a = (A**) malloc(size* sizeof(A*));
    for (int i = 0; i < size; i++)
    {
        a[0][i] = (A*)malloc(size * sizeof(A));
    }
}

A pointer to a pointer is not a two-dimensional array. Additionally, I do not see any attempt to free anything (you perform allocations at line 3 and 6). — Peter - Reinstate Monica
– Peter - Reinstate Monica, Commented Oct 14, 2018 at 18:07
Had you had a look at this answer to your previous question? — alk
– alk, Commented Oct 14, 2018 at 18:07
ok, now I see answer to my last question. Thank you for helping me — user76234
– user76234, Commented Oct 14, 2018 at 18:10
@user76234 If the question is superfluous or obsolete, then please delete it. — Rabbid76
– Rabbid76, Commented Oct 14, 2018 at 18:12

Rabbid76 · Accepted Answer · 2018-10-14 18:07:46Z

5

You have to do the reverse of what you have done when you have allocated the memory.

Free the element pointers in a loop and finally free the pointer to the array:

 void del(A** a, int size)
 {
    for (int i = 0; i < size; i++)
    {
        free(a[i]);
    }
    free(a);
}

answered Oct 14, 2018 at 18:07

Rabbid76

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