Getting the name of a python script that is importing your module

Question

So I want to make myself a module that at some point needs the name of the python script that is importing my module, like argparse does to make the help argument.

ex.

python script.py -h

     USAGE: script.py [-h] [-arg1] [-arg2] . . .

How does argparse acces the name of the script that is importing?

John Gordon · Accepted Answer · 2018-10-17 15:27:48Z

1

sys.argv[0] is the name of the "main" script.

answered Oct 17, 2018 at 15:27

John Gordon

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Comments

mindfolded · Accepted Answer · 2018-10-17 15:23:01Z

0

I believe you can use the built-in __file__ to retrieve the name of the file being run. If you need just the filename and not the path, use os.basename() to strip the path.

answered Oct 17, 2018 at 15:23

mindfolded

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2 Comments

Wiggy A. Over a year ago

Seems like he asked for the path of the file importing the file in question. That doesn't necessarily have to be the file currently being run.

Andrew Over a year ago

it doesn't give the name of the script that is importing the name both file and os.path.basename(file) give , basically, the name/ path of the module

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