Is there a function in PHP to get the name of the subdomain?
In the following example I would like to get the "en" part of the URL:
en.example.com
Here's a one line solution:
array_shift((explode('.', $_SERVER['HTTP_HOST'])));
Or using your example:
array_shift((explode('.', 'en.example.com')));
EDIT: Fixed "only variables should be passed by reference" by adding double parenthesis.
EDIT 2: Starting from PHP 5.4 you can simply do:
explode('.', 'en.example.com')[0];
explode(...)[0] instead of using shift these days? Not been PHPing for several years..Strict Standards: Only variables should be passed by reference.www.en.example.com and thus will return www as subdomain.Uses the parse_url function.
$url = 'http://en.example.com';
$parsedUrl = parse_url($url);
$host = explode('.', $parsedUrl['host']);
$subdomain = $host[0];
echo $subdomain;
For multiple subdomains
$url = 'http://usa.en.example.com';
$parsedUrl = parse_url($url);
$host = explode('.', $parsedUrl['host']);
$subdomains = array_slice($host, 0, count($host) - 2 );
print_r($subdomains);
You can do this by first getting the domain name (e.g. sub.example.com => example.co.uk) and then use strstr to get the subdomains.
$testArray = array(
'sub1.sub2.example.co.uk',
'sub1.example.com',
'example.com',
'sub1.sub2.sub3.example.co.uk',
'sub1.sub2.sub3.example.com',
'sub1.sub2.example.com'
);
foreach($testArray as $k => $v)
{
echo $k." => ".extract_subdomains($v)."\n";
}
function extract_domain($domain)
{
if(preg_match("/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[a-z\.]{2,6})$/i", $domain, $matches))
{
return $matches['domain'];
} else {
return $domain;
}
}
function extract_subdomains($domain)
{
$subdomains = $domain;
$domain = extract_domain($subdomains);
$subdomains = rtrim(strstr($subdomains, $domain, true), '.');
return $subdomains;
}
Outputs:
0 => sub1.sub2
1 => sub1
2 =>
3 => sub1.sub2.sub3
4 => sub1.sub2.sub3
5 => sub1.sub2
for loop, but I had to check their length (to detect if they were a part of the domain like the "co.uk"). Actually, your solution is far more simple than what I was doing. Regex save lives, thanks!pvt.k12.ma.us, health.vn or even k12.ak.us. Also, domains names may be use Chinese or Russian character set so the regex part [a-z\.]{2,6} would not match them. Check out here to have example domains name: publicsuffix.org/list<?php
$url = 'http://user:[email protected]/path?argument=value#anchor';
$array=parse_url($url);
$array['host']=explode('.', $array['host']);
echo $array['host'][0]; // returns 'sub'
?>
As the only reliable source for domain suffixes are the domain registrars, you can't find the subdomain without their knowledge. There is a list with all domain suffixes at https://publicsuffix.org. This site also links to a PHP library: https://github.com/jeremykendall/php-domain-parser.
Please find an example below. I also added the sample for en.test.co.uk which is a domain with a multi suffix (co.uk).
<?php
require_once 'vendor/autoload.php';
$pslManager = new Pdp\PublicSuffixListManager();
$parser = new Pdp\Parser($pslManager->getList());
$host = 'http://en.example.com';
$url = $parser->parseUrl($host);
echo $url->host->subdomain;
$host = 'http://en.test.co.uk';
$url = $parser->parseUrl($host);
echo $url->host->subdomain;
PHP 7.0: Use the explode function and create a list of all the results.
list($subdomain,$host) = explode('.', $_SERVER["SERVER_NAME"]);
Example: sub.domain.com
echo $subdomain;
Result: sub
echo $host;
Result: domain
.co.uk - your snippet will not work with these TLDs preg_match('/(?:http[s]*\:\/\/)*(.*?)\.(?=[^\/]*\..{2,5})/i', $url, $match);
Just read $match[1]
It works perfectly with this list of urls
$url = array(
'http://www.domain.com', // www
'http://domain.com', // --nothing--
'https://domain.com', // --nothing--
'www.domain.com', // www
'domain.com', // --nothing--
'www.domain.com/some/path', // www
'http://sub.domain.com/domain.com', // sub
'опубликованному.значения.ua', // опубликованному ;)
'значения.ua', // --nothing--
'http://sub-domain.domain.net/domain.net', // sub-domain
'sub-domain.third-Level_DomaIN.domain.uk.co/domain.net' // sub-domain
);
foreach ($url as $u) {
preg_match('/(?:http[s]*\:\/\/)*(.*?)\.(?=[^\/]*\..{2,5})/i', $u, $match);
var_dump($match);
}
.ua is the country code for Ukraine.$match[1] part? $match[0] seems unnecessary.$REFERRER = $_SERVER['HTTP_REFERER']; // Or other method to get a URL for decomposition
$domain = substr($REFERRER, strpos($REFERRER, '://')+3);
$domain = substr($domain, 0, strpos($domain, '/'));
// This line will return 'en' of 'en.example.com'
$subdomain = substr($domain, 0, strpos($domain, '.'));
$_SERVER['HTTP_HOST']) then relying on a spoof-able referrer header, assuming that's what the general idea behind the answer is.There isn't really a 100% dynamic solution - I've just been trying to figure it out as well and due to different domain extensions (DTL) this task would be really difficult without actually parsing all these extensions and checking them each time:
.com vs .co.uk vs org.uk
The most reliable option is to define a constant (or database entry etc.) that stores the actual domain name and remove it from the $_SERVER['SERVER_NAME'] using substr()
defined("DOMAIN")
|| define("DOMAIN", 'mymaindomain.co.uk');
function getSubDomain() {
if (empty($_SERVER['SERVER_NAME'])) {
return null;
}
$subDomain = substr($_SERVER['SERVER_NAME'], 0, -(strlen(DOMAIN)));
if (empty($subDomain)) {
return null;
}
return rtrim($subDomain, '.');
}
Now if you're using this function under http://test.mymaindomain.co.uk it will give you test or if you have multiple sub-domain levels http://another.test.mymaindomain.co.uk you'll get another.test - unless of course you update the DOMAIN.
I hope this helps.
Using regex, string functions, parse_url() or their combinations it's not real solution. Just test any of proposed solutions with domain test.en.example.co.uk, there will no any correct result.
Correct solution is use package that parses domain with Public Suffix List. I recomend TLDExtract, here is sample code:
$extract = new LayerShifter\TLDExtract\Extract();
$result = $extract->parse('test.en.example.co.uk');
$result->getSubdomain(); // will return (string) 'test.en'
$result->getSubdomains(); // will return (array) ['test', 'en']
$result->getHostname(); // will return (string) 'example'
$result->getSuffix(); // will return (string) 'co.uk'
What I found the best and short solution is
array_shift(explode(".",$_SERVER['HTTP_HOST']));
For those who get 'Error: Strict Standards: Only variables should be passed by reference.' Use like this:
$env = (explode(".",$_SERVER['HTTP_HOST']));
$env = array_shift($env);
$domain = 'sub.dev.example.com';
$tmp = explode('.', $domain); // split into parts
$subdomain = current($tmp);
print($subdomain); // prints "sub"
As seen in a previous question: How to get the first subdomain with PHP?
Suppose current url = sub.example.com
$host = array_reverse(explode('.', $_SERVER['SERVER_NAME']));
if (count($host) >= 3){
echo "Main domain is = ".$host[1].".".$host[0]." & subdomain is = ".$host[2];
// Main domain is = example.com & subdomain is = sub
} else {
echo "Main domain is = ".$host[1].".".$host[0]." & subdomain not found";
// "Main domain is = example.com & subdomain not found";
}
// For www.abc.en.example.com
$host_Array = explode(".",$_SERVER['HTTP_HOST']); // Get HOST as array www, abc, en, example, com
array_pop($host_Array); array_pop($host_Array); // Remove com and exmaple
array_shift($host_Array); // Remove www (Optional)
echo implode($host_Array, "."); // Combine array abc.en
I know I'm really late to the game, but here goes.
What I did was take the HTTP_HOST server variable ($_SERVER['HTTP_HOST']) and the number of letters in the domain (so for example.com it would be 11).
Then I used the substr function to get the subdomain. I did
$numberOfLettersInSubdomain = strlen($_SERVER['HTTP_HOST'])-12
$subdomain = substr($_SERVER['HTTP_HOST'], $numberOfLettersInSubdomain);
I cut the substring off at 12 instead of 11 because substrings start on 1 for the second parameter. So now if you entered test.example.com, the value of $subdomain would be test.
This is better than using explode because if the subdomain has a . in it, this will not cut it off.
From PHP 5.3 you can use strstr() with true parameter
echo strstr($_SERVER["HTTP_HOST"], '.', true); //prints en
www at string start. A bit too trivial approach.www is actually a subdomain. It's just commonly aliased to the domain name itself for historical reasons.Try this...
$domain = 'en.example.com';
$tmp = explode('.', $domain);
$subdomain = current($tmp);
echo($subdomain); // echo "en"
function get_subdomain($url=""){
if($url==""){
$url = $_SERVER['HTTP_HOST'];
}
$parsedUrl = parse_url($url);
$host = explode('.', $parsedUrl['path']);
$subdomains = array_slice($host, 0, count($host) - 2 );
return implode(".", $subdomains);
}
$host = explode('.', isset($parsedUrl['path']) ? $parsedUrl['path'] : $parsedUrl['host']);Maybe I'm late, but even though the post is old, just as I get to it, many others do.
Today, the wheel is already invented, with a library called php-domain-parser that is active, and in which two mechanisms can be used. One based on the Public Suffix List and one based on the IANA list.
Simple and effective, it allows us to create simple helpers that help us in our project, with the ability to know that the data is maintained, in a world in which the extensions and their variants are very changeable.
Many of the answers given in this post do not pass a battery of unit tests, in which certain current extensions and their variants with multiple levels are checked, and neither with the casuistry of domains with extended characters.
Maybe it serves you, as it served me.
If you only want what comes before the first period:
list($sub) = explode('.', 'en.example.com', 2);
parse_url() to extract the host.
(^|://)(.*)\.and capture the.*? I rather suck at both php and regex, but this comes to mind.en.foo.bar.example.comoren.example.co.uk?