hexadecimal array to binary array

Question

I want to convert this hexadecimal array :

[7,3,2,0,1,9,0,4]

into this one

[0,1,1,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0,0,1,1,0,0,1,0,0,0,0,0,1,0,0]

where you can recognize the first 4 integers is egal to 7 in binary format (0111), and so on.

I tried to use format(x, '04b') but the result is in string format :

['0111','0011','0010','0000','0001','1001','0000','0100']

Consequently I can't use the result as binary array. How to do that ?

One way would be list(map(int,list(''.join(a)))) where a is your current result but it seems a bit ugly. — roganjosh
– roganjosh, Commented Oct 24, 2018 at 13:31
Actually, my first approach could be shortened to list(map(int,''.join(a))) — roganjosh
– roganjosh, Commented Oct 24, 2018 at 13:42
What makes [7,3,2,0,1,9,0,4] a hexadecimal array? It looks like it only contains decimal integers. — martineau
– martineau, Commented Oct 24, 2018 at 13:57
@usr2564301: I know that. I'm asking the OP why they're calling it a hexadecimal array. — martineau
– martineau, Commented Oct 24, 2018 at 14:09
@usr2564301: I believe all integers are binary in computers. What's in the OP question appears to me to be decimal representation of an "array" of them. Let's stop talking about this topic, it's boring. — martineau
– martineau, Commented Oct 24, 2018 at 14:32

ikuamike · Accepted Answer · 2018-10-24 13:56:28Z

1

This one liner will return a list of integers as you want:

hex = [7,3,2,0,1,9,0,4]
list(map(int,"".join([format(x, '04b') for x in hex])))

answered Oct 24, 2018 at 13:56

ikuamike

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blhsing · Accepted Answer · 2018-10-24 14:07:13Z

1

You can use bitwise operations:

h = [7,3,2,0,1,9,0,4]
[i >> b & 1 for i in h for b in range(3, -1, -1)]

This returns:

[0, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0]

answered Oct 24, 2018 at 14:07

blhsing

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roganjosh · Accepted Answer · 2018-10-24 13:41:11Z

0

arr = [7,3,2,0,1,9,0,4]

hexa = ''.join(str(e) for e in arr)

print(bin(int(hexa,16))[2:])

This takes a hexidecimal array and converts it into binary!

edited Oct 24, 2018 at 13:41

roganjosh

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answered Oct 24, 2018 at 13:39

TREVOR HURST

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2 Comments

TREVOR HURST Over a year ago

you and exchange print for x = then, use x.split() to separate it into an array

roganjosh Over a year ago

But it returns a string, and the OP wants a list of integers.

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