Python - Creating folder names based on argument values

Question

I am trying to create a function that would create a folder based on the values passed as arguments. The function has 2 arguments (one argument that stores the store name and the other argument that has a reference date). Given below is the function.

def sales_fn(name,date):
    path = "/Users/user/'%s'/{}"%(name).format(date)

I keep getting an error

 FileNotFoundError: [Errno 2] No such file or directory: "/Users/user/'store_name'{}"

Could anyone guide me where am I going wrong. Thanks.

You're confusing the old % string formatting with .format, try to search online for documentation and examples that use .format you'll find plenty! Side-note: a path shouldn't contain quotes — Nir Alfasi
– Nir Alfasi, Commented Oct 24, 2018 at 18:01
A path can contain quotes if he thinks the username might contain spaces. — mVChr
– mVChr, Commented Oct 24, 2018 at 18:09

mVChr · Accepted Answer · 2018-10-24 18:01:36Z

2

It's strange to use multiple types of string formatting like that. % is the old way, so just use .format():

path = "/Users/user/'{}'/{}".format(name, date)

answered Oct 24, 2018 at 18:01

mVChr

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jar · Accepted Answer · 2018-10-24 18:23:55Z

1

How about f-strings, they are much more elegant-

path = "/Users/user/'%s'/{}"%(name).format(date)

to -

path = f"/Users/user/{name}/{date}"

NOTE: They will work only with Python 3.6+

edited Oct 24, 2018 at 18:23

answered Oct 24, 2018 at 18:17

jar

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