How to replace only string end with number - preg_replace php

Question

Here is my string.

$text = 'I am  [pitch = "high"]Rudratosh Shastri[endpitch]. what is your name ? how  are you? sorry [pause ="3000"] i can not hear you ?[rate="-70.00%"] i still can\'t hear you[endrate] ? [rate="+50.00%"]why i can\'t hear you[endrate] ?';

I want to replace [pause = "3000"] by <break time="3000ms">

I have written following regex but it is selecting till the last "]

\[pause.*\"(\d+)\".*\"]

PHP : $text = preg_replace("/\[pause.*\"(\w+)\".*\"]/", '<break time="$1ms"/>', $text);

If I were to find a solution where the regular expression only selects 'any number'

any number"]

my problem would be solved.

But I am not able to find how to do it.

Do you have any suggestions ?

Wiktor Stribiżew · Accepted Answer · 2018-10-26 07:34:32Z

2

You may use

\[pause[^]]*"(\d+)"]

Or (if there may be something else after the digits):

\[pause[^]]*"(\d+)"[^]]*]
                   ^^^^^

and replace with <break time="$1ms"/>. See the regex demo

Details

\[pause - [pause substring
[^]]* - 0+ chars other than ]
" - a double quotation mark
(\d+) - Group 1: one or more digits
"] - a "] substring.

PHP demo:

$str = 'I am  [pitch = "high"]Rudratosh Shastri[endpitch]. what is your name ? how  are you? sorry [pause ="3000"] i can not hear you ?[rate="-70.00%"] i still can\'t hear you[endrate] ? [rate="+50.00%"]why i can\'t hear you[endrate] ?';
echo preg_replace('~\[pause[^]]*"(\d+)"]~', '<break time="$1ms"/>', $str);
// => I am  [pitch = "high"]Rudratosh Shastri[endpitch]. what is your name ? how  are you? sorry <break time="3000ms"/> i can not hear you ?[rate="-70.00%"] i still can't hear you[endrate] ? [rate="+50.00%"]why i can't hear you[endrate] ?

answered Oct 26, 2018 at 7:34

Wiktor Stribiżew

631k41 gold badges502 silver badges632 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Coder Over a year ago

Thank you much for your the answer.

The fourth bird · Accepted Answer · 2018-10-26 08:27:10Z

Your regex matches too much due to the last part .*\" If you remove that part you would have your match for the current example data, but the first .* still matches any character including for example characters like "[].

What you could do is replace that first .* by matching the equals sign surrounded by horizonal whitespace character like \h*=\h*

Note that you don't have to escape the double quote.

You might use:

\[pause\h*=\h*"(\d+)"]

Regex demo

That will match

\[pause Match [pause
\h* Match zero or more horizontal whitespace characters
= Match =
\h*" Match zero or more horizontal whitespace characters followed by a "
(\d+) Capture in a group one or more digits
"] Match "]

And replace with:

<break time="$1ms"> or use <break time="$1ms"/>

For example:

$text = 'I am  [pitch = "high"]Rudratosh Shastri[endpitch]. what is your name ? how  are you? sorry [pause ="3000"] i can not hear you ?[rate="-70.00%"] i still can\'t hear you[endrate] ? [rate="+50.00%"]why i can\'t hear you[endrate] ?';
$text = preg_replace('/\[pause\h*=\h*"(\d+)"]/', '<break time="$1ms"/>', $text);
echo $text;

Demo

Collectives™ on Stack Overflow

How to replace only string end with number - preg_replace php

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related