I have a problem. I want to assign a path to a variable, so I did this:
customers = ["john", "steve", "robbert", "benjamin"]
for customer in customers:
dataset = "/var/www/test.nl/customer_data/" + str({customer}) + ".csv"
So I was hoping that the output of that variable would be:
/var/www/test.nl/customer_data/john.csv
But that's not the case, because the output I get is:
/var/www/test.nl/customer_data/set(['john']).csv
What am I doing wrong, and how can I fix this?
Here you first make a singleton set that contains that string. As a result it is formatted the wrong way. With:
str({customer})
you thus first construct a set, for example:
>>> {"john"}
{'john'}
>>> type({"john"})
<class 'set'>
and if you then take the str(..) of that set, we get:
>>> str({"john"})
"{'john'}"
So then this is the value we will "fill in", whereas we only want the content of the string customer itself.
You can format these with:
customers = ["john", "steve", "robbert", "benjamin"]
for customer in customers:
dataset = "/var/www/test.nl/customer_data/{}.csv".format(customer)So here {} will be replaced with the string representation of customer, but since customer is already a string, it will thus simply fill in the string.
You have curly braces around the customer variable. Replace
dataset = "/var/www/test.nl/customer_data/" + str({customer}) + ".csv"
with
dataset = "/var/www/test.nl/customer_data/" + str(customer) + ".csv"
Better yet, if on python 3.6 or higher, use f strings:
dataset = f"/var/www/test.nl/customer_data/{customer}.csv"
That might be where you've seen curly braces used for string formatting. The way you're using them, you are defining a set object inline.
