initialization from incompatible pointer type during array initialization

Question

I have below code :

int main()
{
    int* abc[] ={
                    [3] = (&(int[3]){1,2,3}),
                    [2] = (&(int[2]){4,5})
                };
    printf("\n abc[3][1] = %d \n",abc[3][1]);
    return 0;
}

I am trying to set up my array abc , so that specific indexes of the array point to a different array of integers.

Later, I would modify this to use macros so that array is initialized during pre-processing, hence such an approach.

Code works fine but I get a warning :

warning: initialization from incompatible pointer type

Is this because my array abc is declared to point to integer but it is actually pointing to array of integers? How can I make this warning go away?

FormatTry......

gsamaras
– gsamaras

2018-11-05 13:17:50 +00:00
Commented Nov 5, 2018 at 13:17 — gsamaras
– gsamaras, Commented Nov 5, 2018 at 13:17

Lundin · Accepted Answer · 2018-11-05 13:42:24Z

3

The types you're using in the compound literals are incorrect.

The elements of the array are int *, but when using &, the types of the compound literals are int (*)[3] and int (*)[2].

It should be:

int* abc[] ={
                [3] = ((int[3]){1,2,3}),
                [2] = ((int[2]){4,5})
            };

Now int[3] and int[2] both decay to int *.

edited Nov 5, 2018 at 13:42

Lundin

220k47 gold badges281 silver badges446 bronze badges

answered Nov 5, 2018 at 13:18

dbush

233k27 gold badges261 silver badges334 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Lundin Over a year ago

@dbush I took the liberty to edit in a clarification, I hope you don't mind.

dbush Over a year ago

@Lundin No problem. Thanks.

Jianyu Over a year ago

Is there any way to initialize abc without knowing the size of the subarrays?

Collectives™ on Stack Overflow

initialization from incompatible pointer type during array initialization

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related