Javascript: sort() 2 dimensional array

Question

I have a two dimensional array where the first is the distance and second is the object:

[distance][object]

I need to order by distance - I'm trying something like this but it doesn`t work, someone could help me?

lista.sort((a, b) => {return a-b});

and

let t = lista.sort(sortFunction);

sortFunction(a, b) {
    if (a[0] === b[0]) {
        return 0;
    }
    else {
        return (a[0] < b[0]) ? -1 : 1;
    }
}

Can you please provide some real sample input and output?

slider
– slider

2018-11-07 22:36:27 +00:00
Commented Nov 7, 2018 at 22:36 — slider
– slider, Commented Nov 7, 2018 at 22:36

Dacre Denny · Accepted Answer · 2018-11-08 01:19:25Z

2

If I understand your question correctly, the the following should work for you - the idea here is to call .sort() on the "outer array" of your two-dimensional dataset, and pass a comparison function that tests the first element (ie the distance data) of each item being compared:

var data = [
  [22, { object : 22 }],
  [10, { object : 10 }],
  [3, { object : 3 }],
  [50, { object : 50 }]
]

console.log('unsorted:', data)

data.sort((a, b) => {
  return a[0] - b[0]
})

console.log('sorted:', data)

answered Nov 8, 2018 at 1:19

Dacre Denny

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