I had an issue with this regex:
(\{(([^\p{Space}][^\p{Punct}])+)\})
The problem is in number of chars. If I typing even number of chars it's works, when odd - not. I was trying to replace '+' with '?' or '*', but result still the same. How can I fix this?
I expect from this regex to block such strings: {%,$ #fd}. And allow this: {F} or {F242fFSf23}.
Currently, it matches a {, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a }, hence you cannot use 1 char in between {...}.
To fix that, you need to use both the character classes inside bracket expression:
\{[^\p{Punct}\p{Space}]+\}
or
\{[^\p{P}\p{S}\s]+\}
Details
\{ - a { char[^\p{Punct}\p{Space}]+ - 1 or more repetitons (+) of any char that does not belong to the \p{Punct} (punctuation) or \p{Space} (whitespace) class.\} - a }.Note that if the contents between the braces can only include ASCII letters or digits (in regex, [A-Za-z0-9]+), you may even use a mere
\{[A-Za-z0-9]+\}
Disassembling your regex... the reason why it only accepts an even number in between is the following part:
([^\p{Space}][^\p{Punct}])+
This basically means: something which isn't a space, exactly 1 character and something which isn't a ~punct, exactly 1 character and this several times... so exactly 1 + exactly another 1 are exactly 2 characters... and this several times will always be even.
So what you probably rather want is the following:
[^\p{Space}\p{Punct}]+
for the part shown above... which will result in the following for your complete regex:
\{[^\p{Space}\p{Punct}]+}
that of course can be simplified even more. I leave that up to you.
{, then 1 or more repetitions of 2 chars, a non-space and then a non-punctuation, and then a}, hence you cannot use 1 char in between{...}\{[^\p{Punct}\p{Space}]+\}or\{[^\p{P}\p{S}\s]+\}or even\{\p{Alnum}+\}or\{[A-Za-z0-9]+\}