problem in reterving integer value in shellscript

Question

pro* c code: shan.pc

int main()
{
    return 8000;
}

shellscript:

#!/bin/ksh
declare -i rc

shan
rc=$?

echo "$rc";

in script I called proc executable i got an output 128, rather then 8000. how can i receive 8000 in shellscript? please help me out?

solution:

int main()
    {
count=8000;
prinf("counter %d",count); 
        return 0;
    }

#!/bin/ksh
  rc=$(shan | awk '/counter/{print $2}')      
  echo "$rc";

geekosaur · Accepted Answer · 2011-03-16 07:02:06Z

1

You don't; the exit status of a program is restricted to -128 .. 127. printf() it instead and use rc=$(shan) in the script.

answered Mar 16, 2011 at 7:02

geekosaur

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9 Comments

jcrshankar Over a year ago

i gave like this rc=$(shan),no value is getting printted.

geekosaur Over a year ago

Did you change shan.pc to printf the value instead of returning it?

jcrshankar Over a year ago

do u mean int main() { printf(8000);}

geekosaur Over a year ago

int main() { printf("%d\n", 8000); return 0; } You're going to need to learn C if you're going to get anywhere with this.

jcrshankar Over a year ago

i need to receive the value in script, in c i know it will print 8000.i need to echo the value in script which i receive from proc.. i dont need any printf. I am using a counter variable in a loop. i want this value of the counter to be returned to the script...

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