getting substrings in each array index using a delimeter

Question

given an array

String original[]={"string0,10","string1,45","string2,3", "string3,67"};

how would I use the comma as a delimeter to create another array with only the names?

I need an array that looks something like this:

String result[]={"string0","string1","string2", "string3"};

so the second line is your desired output? Have you tried this ? — Damith
– Damith, Commented Nov 9, 2018 at 7:33
@Jibran yes but the name can also have numbers and special characters. I just need to figure out how to get the substring up until the comma at each index of the original array. — Julian
– Julian, Commented Nov 9, 2018 at 7:45
You can try java 8 solution given below by @schidu. It is elegant and will do the work. — Jibran
– Jibran, Commented Nov 9, 2018 at 7:48

Schidu Luca · Accepted Answer · 2018-11-09 07:33:38Z

3

You can use streams and map from java 8 to do it:

String[] strings = Arrays.stream(test)
            .map(string -> string.split(",")[0])
            .toArray(String[]::new);

answered Nov 9, 2018 at 7:33

Schidu Luca

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Deepak Gunasekaran · Accepted Answer · 2018-11-09 07:41:47Z

0

public static void main(String[] args) {
    String original[]={"string0,10","string1,45","string2,3", "string3,67"};
    int len = original.length;
    String result[] = new String[len];
    for(int i=0; i<len;i++) {       
        result[i] = original[i].split(",")[0];      
    }

    System.out.println(Arrays.toString(result));
}

DeclareString result[] array
Iterate the array
Split the record for every Iteration using , as delimiter
Now the split operation will return the array of size 2. It contains name at index 0.
assign the value the result array.

edited Nov 9, 2018 at 7:41

answered Nov 9, 2018 at 7:33

Deepak Gunasekaran

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1 Comment

SPlatten Over a year ago

I would add a check before the assignment to result[I] as depending on the content of original[] there may not be a ',' and you should always check for the possibility of this not being present.

upendra · Accepted Answer · 2018-11-09 17:50:18Z

0

import java.util.Arrays;
import java.util.stream.Collectors;

public class ArraySubstring {

    public static void main (String args[]) {
        String test[]={"string0,10","string1,45","string2,3", "string3,67"};

        String test2[] = Arrays.stream(test).map(s -> s.substring(0, s.indexOf(","))).toArray(String[]::new);
        for (String s : test2) {
            System.out.println(s);
        }
    }
}

edited Nov 9, 2018 at 17:50

answered Nov 9, 2018 at 8:03

upendra

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1 Comment

upendra Over a year ago

I agree this can be much simplified as @Schidu mentioned.

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