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Q2: Implelment the follwoing function ArrPrintMatrix(char *(p)[7]) which prints the content of the matrix[m][7] ={"SHAHBAZ","AYAZ"} in to 3x3 Matrix

Sample Output

S H A                      
H B A                       
Z A Y ..

My question is : here is code only problem i am getting is a space after one name is completed..how to remove that space . I have this question in my assignments , that have to be submitted on sunday (11-11-18).. My code is:

#include<stdio.h>
int main()
{
    void ArrPrintMatrix(char *p);//function declaration
    char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
    ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
    int i;
    for(i=0;i<16;i++)
    {
        if(i>=9)//since 3 by 3 matrix is required
            break;
        if(i==3||i==6||i==9)//changing line since 3 by 3 matrix is needed
            printf("\n");
        printf("%c ",*(p+i));//prininting chracters

    }
}
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2
  • Nasty question. It tells you to write a function like this ArrPrintMatrix(char *(p)[7]) and gives you a string that's 8 characters long ("SHAHBAZ" plus a terminating zero). Commented Nov 9, 2018 at 16:42
  • thank you so much for quick reply . I donot understand hot to use ArrPrintMatrix(char *(p)[7]) and to pass it to function can you please please help me ....please Commented Nov 9, 2018 at 16:46

3 Answers 3

Reset to default
1

You should use char (*p)[8] not char* p

The following code could wrok:

#include<stdio.h>
int main()
{
    void ArrPrintMatrix(char (*p)[8]);//function declaration
    char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
    ArrPrintMatrix(matrix);//calling function with base address

}
void ArrPrintMatrix(char (*p)[8])
{
    // i will point to one of the strings in the set of strings
    // j will point into the string we are inspecting
    // k will count how many characters we have printed
    int i = 0, j = 0, k = 0;

    // we only need to print the first 9 printable characters we find
    while (k != 9)
    {
        // if we have reached the end of an input string (the null-terminator),
        // then move on to the next element in the array, and reset
        // the string pointer to the beginning of the new string
        if (p[i][j] == '\0') {
            ++i;
            j = 0;
        }

        // print the character we are now pointing at,
        // and increment the string pointer
        printf("%c ", p[i][j++]);

        // keep count of how many characters we have printed
        ++k;

        // if k is divisible by 3, start a new row
        if(k%3 == 0)
            printf("\n");
    }
}
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2 Comments

perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
can you please tech me your code by commenting or something like dry run..I would be thankfull
0

As a follow-on to my other answer, if you do use my logic to skip over the '\0' that terminates the strings, you will need to use a different variable to keep track of how many characters you've actually printed, and just let i keep track of where you are in the input string(s). Like so:

#include<stdio.h>
int main()
{
    void ArrPrintMatrix(char *p);//function declaration
    char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
    ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
    int i, j;
    for(i=0, j=0;i<16;i++)
    {
        if(j>=9)//since 3 by 3 matrix is required
            break;
        if(j==3||j==6||j==9)//changing line since 3 by 3 matrix is needed
            printf("\n");
        if (*(p+i)==0) continue; //don't try to print the trailing '\0'
        printf("%c ",*(p+i));//prininting chracters
        j++; //increment counter of characters actually printed

    }
}

Output:

S H A 
H B A 
Z A Y

Note the use of the j variable, and how it is incremented with j++ only after actually printing a character.

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13 Comments

if (*(p+i)==0) continue; //don't try to print the trailing '\0' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
'0' is very different from 0; '\0' on the other hand equates to 0
you could use either if (*(p+i)==0) or if (*(p+i)=='\0'), but not if *(p+j)=='0', which is what you have in your comment
can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '\0') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("\n"); } }
Sorry about that i have implemented your answer . But just for the sake of understanding i asked you, cause i like your explanation...
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0

What you are missing is that there is a trailing '\0' at the end of SHAHBAZ, which you are also "printing", but because '\0' does not have a character representation, you are seeing what looks like an 'extra' space.

Here is the smallest change I can think of to address this exact problem; add:

if (*(p+i)==0) continue; //don't try to print the trailing '\0'

just above your existing line:

printf("%c ",*(p+i));//prininting chracters

Output:

S H A 
H B A 
Z A

There are other things I would do differently than how you are doing them, but this addresses your exact question, using your coding style.

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