I have a few files in the folder and I want to find out the content and match its file name. But when I use re.search to achieve my goal I can only get ‘None’. Anyone could help?
import re
xe = r'D:\ABC\cc123.xml'
re.search('cc*?.xml', xe)
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also, for future reference, you can use something like pythex to test your regular expressions, and python regex documentation for syntaxrobotHamster– robotHamster2018-11-12 02:33:56 +00:00Commented Nov 12, 2018 at 2:33
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2 Answers
(Though there is an accepted answer, I don't feel the answer is clear for other people, and there is still room to improve, so I added a new answer here)
The problem is simply OP is using a wrong regex: cc*?.xml
* means any occurrence of the preceding token (which means c in your case)
*? is a reluctant match any occurrence.
. means any character
Which means what you are trying to do is match a string which is:
- a
c - followed by any occurrence of c
- followed by any character
- followed by
xml
Example of matching strings are c.xml ccccccAxml etc.
What you were trying to do, I believe is
cc.*?\.xml
which means matching
cc.*?: followed by any occurrence of any character, matching as few as possible\.: followed by a dot (note the difference of\.vs.)- followed by
xml
Comments
How about something like this with a small tweak?
import re
xe = 'D:\ABC\cc123.xml'
print (re.search('cc.*?.xml', xe).group())
output:
cc123.xml
