I have been struggling with this bug. When using MATLAB to read a binary file that contains three columns of numbers in float formats.
I am reading one number at a time using this line.
pt(j) = fread(fid,1,'float','a');
I have found that sometimes (rarely) MATLAB instead of reading four bytes for a float, it uses 5 bytes. And it misses up the rest of the reading. I am not sure if the file is corrupted or MATLAB has a bug there. When I printed the file as a txt and read it in txt everything works well.
As a work around here is what I did:
cur = ftell(fid);
if (cur - prev)~= 4
pt(j) = 0; % I m throwing this reading away for the sake of saving the rest of the data. This is not ideal
cur = prev +4;
fseek(fid, cur,'bof');
end
prev = cur;
I tried different combinations of different formats float32 float64 etc... nothing works MATLAB always read 5 bytes instead of 4 at this particular location.
EDIT: To solve it based on Chris's answer. I was using this command to open the file.
fid = fopen(fname,'rt');
I replaced it with this
fid = fopen(fname,'r');
pt(j) = fread(fid,1,'float',0,'a');. In your original statement, your variableais in place of theskipparameter ...