How to loop through an object array and output the array with a specific object property javascript

Question

var obo = [{
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    }, {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    }, {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    }
]

I want to loop through and return the array. i have tried splice its not working

var obo = [{
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "userid": "tomi",
        "location": "kwara"
    }
]

Am trying to populate the array so as not to have parcelid in it

What is your specific property, which property in the array are you looking for? — squeekyDave
– squeekyDave, Commented Nov 15, 2018 at 16:22

Mohammad Usman · Accepted Answer · 2018-11-15 16:25:16Z

4

You can use .map() with some object destructuring:

var data = [
  {"parcelId": "009", "userid": "tomi", "location": "kwara"},
  {"parcelId": "009", "userid": "tomi", "location": "kwara"},
  {"parcelId": "009", "userid": "tomi", "location": "kwara"}
];

var result = data.map(({userid, location, ...rest}) => ({userid, location}));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

References:

edited Nov 15, 2018 at 16:25

answered Nov 15, 2018 at 16:20

Mohammad Usman

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Comments

Mohammad · Accepted Answer · 2018-11-15 16:21:27Z

0

You need to use .map()

obo = obo.map(function(item){
  return {
    userid: item.userid,
    location: item.location
  };
});

var obo = [
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  }
];

obo = obo.map(function(item){
  return {
    userid: item.userid,
    location: item.location
  };
});
console.log(obo);

edited Nov 15, 2018 at 16:21

answered Nov 15, 2018 at 16:20

Mohammad

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1 Comment

charlietfl Over a year ago

Since delete mutates original can do it in any loop. No real need to create new array using map() if using mutation approach

A l w a y s S u n n y · Accepted Answer · 2018-11-15 16:23:44Z

0

How about that with Array.prototype.map()?

var obo = [{
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  }
]

var expected = [];

obo.map((elm, ind) => {
  expected.push({
    "userid": elm.userid,
    "location": elm.location
  })
})
console.log(expected)

answered Nov 15, 2018 at 16:23

A l w a y s S u n n y

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Comments

lloydaf · Accepted Answer · 2018-11-15 16:24:45Z

0

You can try something like this

obo = obo.map(el => {
  let obj = {
    userid: el.userid,
    location: el.location
  };
  return obj;
});

or for a one liner, you can do this

obo = obo.map(({userid,location})=>({userid,location})));

answered Nov 15, 2018 at 16:24

lloydaf

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