I have created a list
let keywords = ['do', 'if', 'in', 'for', 'new', 'try', 'for','var'];
now I'm able to filter based on the string and I'm able to sort in descending and ascending order also.
But I'm unable to sort based on the string,
EX:- I need to sort the list with 'for' (for needs to come on the top of the list and remaining will be as it is).
Basically you just need to change the callback of the sort function:
let keywords = ['do', 'if', 'in', 'for', 'new', 'try', 'for','var'];
const sortWithWord = (words, firstWord) => words.sort((a, b) => {
if (a === firstWord) return -1;
return a.localeCompare(b);
});
//will print ["new", "do", "for", "for", "if", "in", "try", "var"]
console.log(sortWithWord(keywords, "new"));
The condition for sorting can be different of course, but if you want a certain word to be first, you'll have to return a negative value when it is compared.
As far as I understand, you want to slice sorted list, like this:
keywords.sort();
var result = keywords.slice(keywords.findIndex(function(item){ return item == "for"; }));
let keywords = ['do', 'if', 'in', 'for', 'new', 'try', 'for','var'];
let spliceArray = keywords; //For this line there is for sure a more elegant solution.
const queryIndex = keywords.findIndex(entry => entry === 'for');
spliceArray.splice(queryIndex, 1);
const newKeywords = [keywords[queryIndex], ...spliceArray];
