How to pass from a binary char array to int array in python? [duplicate]

Question

I have this array "m":

m = ['0000', '0001', '0010', '0011', '1111']

How could I use a lambda function to change its format to:

n1 = [0,0,0,0,0,0,0,1,0,0,1,0,0,0,1,1,1,1,1,1]

or to:

n2 = [[0,0,0,0],[0,0,0,1],[0,0,1,0],[0,0,1,1],[1,1,1,1]]

?

You can create n2 with list comprehensions: n2 = [[int(char_i) for char_i in char] for char in m] — vinsce
– vinsce, Commented Nov 21, 2018 at 22:09
n0 = [list(item) for item in m]; n1 = [int(i) for lst in n0 for i in lst]; n2 = [[int(i) for i in lst] for lst in n0] — berkelem
– berkelem, Commented Nov 21, 2018 at 22:17

greg-bt · Accepted Answer · 2018-11-21 22:28:28Z

0

m = ['0000', '0001', '0010', '0011', '1111']
funct = lambda m: [int(x) for x in ''.join(m)];

This will express list "m" as list "n1" with a lambda function as requested.

answered Nov 21, 2018 at 22:02

greg-bt

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3 Comments

Could I do it without loop? Maybe lambda function

n1 = [int(x) for x in ''.join(m)]

funct = lambda m: [int(x) for x in ''.join(m)];