Sort string in array

Question

I have the following array of age groups:

["35 - 44", "18 - 34", "55+", "45 - 54"]

I want to sort it so that I have:

["18 - 34", "35 - 44", "45 - 54", "55+"]

What I have so far is:

arr.map(item => parseInt(item, 10)).sort((a, b) => a - b)

Which gives me:

[18, 25, 35, 65]

But I don't know what to do now with it.

Thanks for help.

CertainPerformance · Accepted Answer · 2018-11-22 17:11:22Z

3

Don't map it through parseInt, otherwise the non-numbers past the beginning of the string will be dropped. Just sort the plain array of strings with localeCompare:

console.log(
  ["35 - 44", "18 - 34", "55+", "45 - 54"].sort((a, b) => a.localeCompare(b))
);

To be a bit more flexible, if single-digit ranges exist too, use the numeric: true option as well:

console.log(
  ["35 - 44", "1-2", "3-4", "18 - 34", "55+", "45 - 54"]
    .sort((a, b) => a.localeCompare(b, undefined, {numeric: true}))
);

answered Nov 22, 2018 at 17:11

CertainPerformance

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2 Comments

CertainPerformance Over a year ago

That's what { numeric: true } takes care of.

Jonas Høgh Over a year ago

Sorry...missed that beyond the scrollbar ,😯

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