Python - questionable json response

Question

I am very new to python and attempting to parse through what appears to be JSON data.

import requests
import json

URL = "http://myip/cgi-bin/lun/luci/;stok=/login?form=login"

payload = {
'operation': 'login',
'username': 'someuser',
'password': 'somepassword'
}

session = requests.session()
r = requests.post(URL, data=payload)

print (r.json())

What I get back is:

{u'data': {u'stok': u'0c2f16c954cd2cafccfaf1bf50000ac6'}, u'success': True}

I need to use the random collection of letters/numbers in the single quote 0c2f16c954cd2cafccfaf1bf50000ac6 (it changes every time). I dont see any double quotes in this response. So a few questions:

I dont see any double quotes in the response. Is this still json?
What would be the best way to assign that middle part of random characters to a variable so I can use it in a request url I need to build next?

not pretty sure but isn't it return a dict instance? (decoded json) — apple apple
– apple apple, Commented Nov 24, 2018 at 5:33
The json() method does not return JSON as the name would imply. It returns the parsed JSON data already. — Klaus D.
– Klaus D., Commented Nov 24, 2018 at 5:36
And just a hint: If you start learning Python, start with Python 3, version 2 is shortly before retirement. — Klaus D.
– Klaus D., Commented Nov 24, 2018 at 5:38

jwodder · Accepted Answer · 2018-11-24 05:36:30Z

3

I dont see any double quotes in the response. Is this still json?

It was JSON. r.json() deserialized the JSON response to a Python dict, and then print printed that dict.

What would be the best way to assign that middle part of random characters to a variable so I can use it in a request url I need to build next?

a_variable = r.json()["data"]["stok"]

answered Nov 24, 2018 at 5:36

jwodder

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