how to map the string using python

Question

this is my code :

a= ''' ddwqqf{x}'''
def b():
    ...

c=b(a,{'x':'!!!!!'})
print c

i want to get ddwqqf!!!!! ,

so how to create the b function ,

thanks

updated:

but how to do this thing :

a= ''' ddwqqf{x},{'a':'aaaa'}'''

c = a.format(x="!!!!!")

d= open('a.txt','a')
d.write(c)

it show error :

Traceback (most recent call last):
  File "d.py", line 8, in <module>
    c = a.format(x="!!!!!")
KeyError: "'a'"

updated2:

this is the string:

'''
{
    'skill': {x_1},
    'power': {x_2},
    'magic': {x_3},
    'level': {x_4},
    'weapon': {
        0 : {
            'item': {
                'weight': 40,
                'target': 1,
                'defence': 100,
                'name': u'\uff75\uff70\uff78\uff7f\uff70\uff84',
                'attack': 100,
                'type': 1
            },
        },
        1 : {
            'item': {
                'weight': 40,
                'target': 1,
                'defence': 100,
                'name': u'\uff75\uff70\uff78\uff7f\uff70\uff84',
                'attack': 100,
                'type': 1
            },
        },
        2 : {
            'item': {
                'weight': 40,
                'target': 1,
                'defence': 100,
                'name': u'\uff75\uff70\uff78\uff7f\uff70\uff84',
                'attack': 100,
                'type': 1
            },
        }
       ......
    }
}
'''

What are you trying to achieve? Your second example is very confusing. — Björn Pollex
– Björn Pollex, Commented Mar 18, 2011 at 10:41
i want to map many different Variable into a dict , and create many dict like this . — zjm1126
– zjm1126, Commented Mar 18, 2011 at 11:04

Sven Marnach · Accepted Answer · 2011-03-18 12:06:08Z

3

Try

def b(a, d):
    return a.format(**d)

This works in Python 2.6 or above. Of course you would not need to define a function for this:

a = " ddwqqf{x}"
c = a.format(x="!!!!!")

will be enough.

Edit regarding your update:

a = " ddwqqf{x},{{'a':'aaaa'}}"

to avoid substitutions for the second pair of braces.

Another Edit: I don't really know where your string comes from and what's the context of all this. One solution might be

import re
d = {"x_1": "1", "x_2": "2", "x_3": "3", "x_4": "4"}
re.sub(r"\{([a-z_0-9]+)\}", lambda m: d[m.group(1)], s)

where s is your string.

edited Mar 18, 2011 at 12:06

answered Mar 18, 2011 at 10:20

Sven Marnach

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1 Comment

zjm1126 Over a year ago

did you have other way to do this , because the string is very big , if i change {} to {{}} , that is a hard work to me . look the updated2 .

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