cannot access the array using php

Question

i have created an array using php something like this

$array1=array()

for($i=0;$i<5;$i++)
{
  $array1[$i]=somevalue;
  for($y=0;$y<$i;$y++)
  {
    print_r($array1[$y]);
  }
}

it does not print the value.

Can you please write your array? your array on top has no vallues.. ;) — René Höhle
– René Höhle, Commented Mar 18, 2011 at 11:46
something like this doesn't help us find your actual problem. Are you getting any errors? have you got all error reporting turned on. What is your actual code? — Jacob
– Jacob, Commented Mar 18, 2011 at 11:48
are you aware the second loop will be printing the array many times even when [0] is set but the rest are not? — MrPHP
– MrPHP, Commented Mar 18, 2011 at 11:49
there are some syntax errors in your code. If it's the real code you posted here, you have to correct them and it will work. if you're actually running another code, you have to post it here. — Your Common Sense
– Your Common Sense, Commented Mar 18, 2011 at 11:49

Jon · Accepted Answer · 2011-03-18 11:49:48Z

1

If nothing else, you should move the inner loop out:

for($i=0;$i<5;$i++)
{
    $array1[$i]=somevalue;
}

for($y=0;$y<5;$y++)
{
    print_r($array1[$y]);
}

answered Mar 18, 2011 at 11:49

Jon

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2 Comments

Belinda Over a year ago

$i is not going to be available outside the first for loop

Jon Over a year ago

@Belinda: Copy/paste programming is bad :) Thanks for the catch.

Syed Absar · Accepted Answer · 2011-03-18 11:54:57Z

1

I just ran this code, the only change i made was putting a semicolon in the first line ;)

<?php

$array1=array();

for($i=0;$i<5;$i++)
{
  $array1[$i]="abcd";
  for($y=0;$y<$i;$y++)
  {
    print_r($array1[$y]);
  }
}

?>

Output: abcdabcdabcdabcdabcdabcdabcdabcdabcdabcd

answered Mar 18, 2011 at 11:54

Syed Absar

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Comments

Richard Parnaby-King · Accepted Answer · 2011-03-18 12:18:49Z

1

Based on @Jon's answer:

$array1 = array();
for($i=0;$i<5;$i++)
{
    $array1[$i]=somevalue;
}

$count = count($array1);

for($y=0;$y<$count;$y++)
{
    print_r($array1[$y]);
}

You can put the count function in the for loop, but that's bad practice. Also, if you are trying to get the value of EVERY value in the array, try a foreach instead.

$array1 = array();
for($i=0;$i<5;$i++)
{
    $array1[$i]=somevalue;
}
foreach($array1 as $value)
{
  print_r($value);
}

answered Mar 18, 2011 at 12:18

Richard Parnaby-King

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Comments

gnur · Accepted Answer · 2011-03-18 11:54:13Z

0

Because of the way how print_r works, it is silly to put it inside a loop, this will give you actual output and is error free :).

$array1=array();

for($i=0;$i<5;$i++)
{
  $array1[$i]='somevalue';
}
print_r($array1);

answered Mar 18, 2011 at 11:54

gnur

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Comments

Mark Baker · Accepted Answer · 2011-03-18 12:07:36Z

0

for($y=0;$y<$i;$y++)

Your display loop isn't displaying the entry you've just added as $array[$i], because you're looping $y while it's less than $i

for($y=0;$y<=$i;$y++)

answered Mar 18, 2011 at 12:07

Mark Baker

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