Javascript: Searching substring pattern and returning found string

Question

I have a string composed by several fields. Two of which will always vary in length. I could simply use substring if all fields have fixed lengths.

Sample:

48001MCAbastillas2200800046300017100518110555130000123

The fields are divided like this:

480 | 01 | MCAbastillas | 2200800046300017 | 100518 | 110555 | 130000 | 123

The bolded fields are the fields that varies in length. They represent a name and a amount, respectively. I already posted this question but I mistakenly tagged it with Java. I tried to interpret the provided answers into Javascript but being no expert in it, I spent all day producing no results :(

So do you want to split the first string into the components you've given or do you just want to get the bold items you've listed from the string — Nick Parsons
– Nick Parsons, Commented Nov 28, 2018 at 10:02
The will vary in value but the length will always be the same — Uzi
– Uzi, Commented Nov 28, 2018 at 10:02
Very little information to go on. Can you confirm that the 6th character is always the start of a random length of letters until another digit is reached? — Tigger
– Tigger, Commented Nov 28, 2018 at 10:03

kakamg0 · Accepted Answer · 2018-11-28 10:13:23Z

4

You can use regular expression to capture the groups

const regex = /^(.{3})(.{2})(\D+)(.{16})(.{6})(.{6})(\d+)(.{3})$/
const str = '48001MCAbastillas2200800046300017100518110555130000123'
const values = str.match(regex)
console.log(values)

answered Nov 28, 2018 at 10:13

kakamg0

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3 Comments

Osakr Over a year ago

I think this is the more accurate solution

Uzi Over a year ago

I just have to ignore the first element of the array since it returns the original string followed by the separated set. Thanks. This works for me.

kakamg0 Over a year ago

Yes, the first element is the string that matches the regular expression.

Nick Parsons · Accepted Answer · 2018-11-28 10:23:05Z

2

var input = '48001MCAbastillas2200800046300017100518110555130000123';
// match parts with regex
var match = input.match(/^(.{3})(.{2})([a-zA-Z]+)(.{16})(.{6})(.{6})(\d+)(.{3})$/);
// remove first element (full matching input)
match.shift();
// build output
var output = match.join(' | ');
console.log(output);

edited Nov 28, 2018 at 10:23

Nick Parsons

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answered Nov 28, 2018 at 10:17

Apolo

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Comments

user10616833 · Accepted Answer · 2018-11-28 10:25:11Z

0

const test = [
  '48001MCAbastillas2200800046300017100518110555130000123',
  '48001MCAbasti2200800046300017100518110555130000123',
  '48001MCAbastillasXYZ2200800046300017100518110555130000123',
  '48001MCAbastillas2200800046300017100518110555130000999123',
  '48001MCAbastillas2200800046300017100518110555130123',
  '48001MCAbastillasXYZ2200800046300017100518110555130000999123',
  '48001MCAbasti220080004630001710051811055513123'
]

const p = /(?<name>\D+)(\d{28})(?<amount>\d+)(\d{3}$)/

console.log (test.map (s => s.match (p).groups))

answered Nov 28, 2018 at 10:25

user10616833

Comments

Tigger · Accepted Answer · 2018-11-28 10:29:40Z

A more complex version that breaks all the parts based on known values. The regex answer is the way to go.

var r1 = "48001MCAbastillas2200800046300017100518110555130000123";
var r2 = "48001RANDOM220080004630001710051811055512345123";

function extract(str) {
    var i = 5,max = str.length;
    var parts = [], cut1, cut2 = (max - 3);
    for(;i<max;i++) {
        if (! isNaN(parseInt(str[i]))) {
            cut1 = i;
            break;
        }
    }
    parts.push(str.substr(0,3));
    parts.push(str.substr(3,2));
    parts.push(str.substr(5,(cut1 - 5)));
    parts.push(str.substr(cut1,16));
    parts.push(str.substr((cut1 + 16),6));
    parts.push(str.substr((cut1 + 16 + 6),6));
    parts.push(str.substr((cut1 + 16 + 12),(cut2 - (cut1 + 16 + 12))));
    parts.push(str.substr(cut2,3));      
    return parts;
}

console.log(extract(r1));
console.log(extract(r2));

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