what is the default index value in array? [duplicate]

Question

i came across a code in java that doesn't have a array initialization. when there is an increment in the value,it changes to 1.

import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {
  public static void main(String args[]){
    int ar1[] = new int[26];
    String first="abc";

    for (int i = 0; i < first.length(); i++) {
      ar1[first.charAt(i) - 'a']++;
      System.out.println(ar1[i]);
    }



  }


}

the output is 1 1 1. how does that happen

The default value for int[] is 0. This, int ar1[] = new int[26]; fills the array with twenty-six zeros. — Elliott Frisch
– Elliott Frisch, Commented Nov 29, 2018 at 5:32
It happens because the letters a, b, and c, only appear once in your input string. Take a string that has a appearing more than once, and your code should correctly record the count. — Tim Biegeleisen
– Tim Biegeleisen, Commented Nov 29, 2018 at 5:37

LonelyCpp · Accepted Answer · 2018-11-29 05:40:15Z

1

The default value is zero.

ar1[first.charAt(i) - 'a']++; increments the value which corresponds to the particular letter. What it basically does is count the frequency of letters in a string.

in abc, a is ar[0], b is ar1[1], and so on

answered Nov 29, 2018 at 5:40

LonelyCpp

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