RxJS and Typescript catch error with the same type

Question

I use RxJS and I need to return an observable of that type im my method: Observable<MyStuff>

When I want to throw an error I use:

import { throwError } from "rxjs";
/// ... stuff
return throwError('Error stuff invalid');

throwError return an Observable<never> and it's not the same type as Observable<MyStuff>

I want to throw an error with that type: Observable<MyStuff> I don't want to change the return type of my function if it's possible

What is the best practice to handle error with observables ?

Where you have an Observable with type Observable<MyStuff>? — martin
– martin, Commented Nov 30, 2018 at 9:24

Mehdi Bahra · Accepted Answer · 2018-11-30 09:31:07Z

2

You can throw an error without necessarily using ThrowError from rxjs , you can do it in this way , you replace return ThrowError("Your error"); with throw "Error";

and simply catch it when subscribing to your observable like follow YourrReturnedObservable.subscribe(successData => {Your code logic } , err => { // catch exceptions here} );

answered Nov 30, 2018 at 9:31

Mehdi Bahra

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1 Comment

uligerri-6156 Over a year ago

Just perfect, yeah so now I think when you are on a pipe you have to just throw and It will go to the error handling

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