I am using the range() function to create an array. However, I want the keys to be the same as the value. This is ok when i do range(0, 10) as the index starts from 0, however if i do range(1, 11), the index will still start from 0, so it ends up 0=>1 when i want it to be 1=>1
How can I use range() to create an array where the key is the same as the value?
How about array_combine?
$b = array_combine(range(1,10), range(1,10));
or (as suggested in comments):
$b = array_combine($r = range(1, 10), $r)
array_combine($r = range(1, 10), $r) avoid recall range in 2 times.Or you did it this way:
$b = array_slice(range(0,10), 1, NULL, TRUE);
Find the output here: http://codepad.org/gx9QH7ES
There is no out of the box solution for this. You will have to create the array yourself, like so:
$temp = array();
foreach(range(1, 11) as $n) {
$temp[$n] = $n;
}
But, more importantly, why do you need this? You can just use the value itself?
<?php
function createArray($start, $end){
$arr = array();
foreach(range($start, $end) as $number){
$arr[$number] = $number;
}
return $arr;
}
print_r(createArray(1, 10));
?>
See output here: http://codepad.org/Z4lFSyMy
<?php
$array = array();
foreach (range(1,11) as $r)
$array[$r] = $r;
print_r($array);
?>
Create a function to make this:
if (! function_exists('sequence_equal'))
{
function sequence_equal($low, $hight, $step = 1)
{
return array_combine($range = range($low, $hight, $step), $range);
}
}
Using:
print_r(sequence_equal(1, 10, 2));
Output:
array (
1 => 1,
3 => 3,
5 => 5,
7 => 7,
9 => 9,
)
In PHP 5.5 >= you can use Generator to make this:
function sequence_equal($low, $hight, $step = 1)
{
for ($i = $low; $i < $hight; $i += $step) {
yield $i => $i;
}
}
