json encode for following array

Question

i have following array . i want to json_encode for this array Result like [{"dietary_options":"234"},{"dietary_options":"123"}] using array method not for loop.

Array
(
[0] => Array
    (
        [dietary_options] => 
    )

[1] => Array
    (
        [dietary_options] => 
    )

[2] => Array
    (
        [dietary_options] => 
    )

[3] => Array
    (
        [dietary_options] => 
    )

[4] => Array
    (
        [dietary_options] =>234 
    )

[5] => Array
    (
        [dietary_options] => 123
    )

)

and why is it that you can't use a for or a foreach? it just takes a few lines using them — Kevin
– Kevin, Commented Dec 5, 2018 at 6:37
first priority to using array function . i already done with for loop but it is good if using array function. — Asif patel
– Asif patel, Commented Dec 5, 2018 at 6:41
@SvenLiivak no its not working its return null too. i dont want that . — Asif patel
– Asif patel, Commented Dec 5, 2018 at 6:42

MH2K9 · Accepted Answer · 2018-12-05 06:59:49Z

1

Simply array_filter is the easy way

$data = json_encode(array_filter($data, function ($item) { 
    return !!$item['dietary_options'];
}));

answered Dec 5, 2018 at 6:59

MH2K9

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Comments

Asif patel · Accepted Answer · 2018-12-05 10:39:52Z

0

Try this code,

 $data = array(array('dietary_options'=>''),
                  array('dietary_options'=>'one'),
                 array('dietary_options'=>'two'));


$data = array_map('array_filter', $data);
$data = array_values(array_filter($data));
print_r(json_encode($data,true));
// print_r(json_encode(array_filter($data),true));

edited Dec 5, 2018 at 10:39

Asif patel

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answered Dec 5, 2018 at 6:46

Kmg Kumar

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1 Comment

Asif patel Over a year ago

Thanks Work for me but u don't need to be write array_filter in json_encode print_r(json_encode($data,true)); @kmg kumar

JavidRathod · Accepted Answer · 2018-12-05 07:04:47Z

0

please try below code.

$data = array(array("dietary_options"=>""),array("dietary_options"=>"789"),array("dietary_options"=>"123456"));
$data = array_filter(array_map('array_filter', $data));

echo json_encode(array_values($data));

answered Dec 5, 2018 at 7:04

JavidRathod

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Comments

Crysis · Accepted Answer · 2018-12-05 07:06:30Z

0

This works fine for me,

print_r(json_encode(array_filter($myArray)));

answered Dec 5, 2018 at 7:06

Crysis

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Comments

Kanewilliam · Accepted Answer · 2018-12-05 07:07:02Z

0

try this . It's working as your expecting format without loop.

$array=array(
array("dietary_options"=>"234"),
array("dietary_options"=>""),
array("dietary_options"=>""),
array("dietary_options"=>"123")
);

$array_data = array_map('array_filter', $array);
$array_data = array_filter($array_data);
$array_data = array_values($array_data);
print_r(json_encode($array_data));

edited Dec 5, 2018 at 7:07

Kanewilliam

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answered Dec 5, 2018 at 6:52

VinothRaja

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3 Comments

Kmg Kumar Over a year ago

hey, did you check your code ?, they gives the object in json value.

Asif patel Over a year ago

{"5":{"dietary_options":"234"},"7":{"dietary_options":"123"}} i got this kind of result i want [{"dietary_options":"234"},{"dietary_options":"123"}] .. BTW thanks ... @VinothRaja

Kmg Kumar Over a year ago

Hi @Kanewilliam , could you explain what the different between VinothRaja and Kmg kumar answer ?

Zamir · Accepted Answer · 2018-12-05 07:59:33Z

0

php array_filter good option.

$data = array(
            array("dietary_options" => ''),
            array("dietary_options" => ''),
            array("dietary_options" => ''),
            array("dietary_options" => 123),
            array("dietary_options" => 234),
        );
return new JsonResponse(array_values(array_filter($data, function($k){
        return !!$k["dietary_options"];
})));

answered Dec 5, 2018 at 7:59

Zamir

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