Let's take:
my_list=[["a","b","c"],["d","e","f"],["g","h","i"],["j","k","l"]]
And the result I'm looking for:
0. a _ b (c)
1. d _ e (f)
2. g _ h (j)
3. j _ k (l)
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Do you want to get each element of your list? like [a,b,c] or only [a]?Aybars– Aybars2018-12-05 15:32:48 +00:00Commented Dec 5, 2018 at 15:32
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1My understanding of your question as it is given is that for each sub-list, you want to print a number, first element, underscore, second element and finally third element in parentheses. Is that correct?Martin Frodl– Martin Frodl2018-12-05 15:34:29 +00:00Commented Dec 5, 2018 at 15:34
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It is not clear what you are asking for; the expected output isn't in any Python structure and you didn't specify the rules to have the expected outputGsk– Gsk2018-12-05 15:35:52 +00:00Commented Dec 5, 2018 at 15:35
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yes, it is exactly what i wantThịnh Hưng– Thịnh Hưng2018-12-05 16:10:52 +00:00Commented Dec 5, 2018 at 16:10
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4 Answers
To get exactly your output printed in the console, iterate over the outer list and use enumerate and str.format:
values = [["a","b","c"],["d","e","f"],["g","h","i"],["j","k","l"]]
for i, x in enumerate(values):
print("{}. {} _ {} ({})".format(i, *x))
# 0. a _ b (c)
# 1. d _ e (f)
# 2. g _ h (i)
# 3. j _ k (l)
Comments
Assuming a,b,c... are integers
A = [[8, 7, 2], [1, 4, 12], [6, 5, 4]]
B = "\n".join(["%d_%d(%d)" % tuple(a) for a in A])
print(B)
if these are strings (not very clear in question), just use %s instead of %d
Comments
Other option:
lst = [['a','b','c'],['d','e','f'],['g','h','i'],['j','k','l']]
lines = [x[0]+'_'+x[1]+' ('+x[2]+')' for x in lst]
for i, line in enumerate(lines):
print( str(i+1) + '. ' + line)
It returns:
# 1. a_b (c)
# 2. d_e (f)
# 3. g_h (i)
# 4. j_k (l)
Comments
Try this one:
print '\n'.join(str(n) +'. '+e[0] + ' _'+ e[1] + ' ('+e[2]+')' for n,e in enumerate(my_list))
You should have:
0. a _b (c)
1. d _e (f)
2. g _h (i)
3. j _k (l)
