TypeScript: How to types destructured parameters using spread syntax?

Question

There exists the exact same question, but it was about array parameters.

How do I type str in this case?

const func = ({str, ...rest})=>{//doStuff}

This did not work:

const func = ({str, ...rest}:{str:string})=>{//doStuff}

This neither:

const func = ({str, ...rest}:{str:string; ...rest:any[]})=>{//doStuff}

Please show how your function is supposed to look like and work in JS — miensol
– miensol, Commented Dec 6, 2018 at 11:30

Nurbol Alpysbayev · Accepted Answer · 2018-12-06 11:43:11Z

1

You want this:

type Func = (arg: {str: string} & {[key: string]: any}) => any

const func: Func = ({str, ...rest})=>{/* doStuff */}

answered Dec 6, 2018 at 11:43

Nurbol Alpysbayev

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