php Notice : Array to string conversion in

Question

I've the following array$_SESSION['survey_ans'][]=$records; and will get the result withvar_dump($_SESSION['survey_ans']);

array(6) {
    [0]=> array(1) {
        [1]=> string(5) "vpoor" 
    } 
    [1]=> array(1) { 
        [10]=> string(4) "poor" 
    } 
    [2]=> array(1) { 
        [6]=> string(7) "average" 
    } 
    [3]=> array(1) { 
        [11]=> string(4) "good" 
    } 
    [4]=> array(1) { 
        [12]=> string(5) "vgood" 
    } 
    [5]=> array(1) { 
        [13]=> string(4) "good" 
    } 
}

But when I run this

foreach($_SESSION['survey_ans'] as $key=>$value) {
    echo $key."-".$value."<br />";
}

I will get the error "Notice : Array to string conversion in ". So how do I get the result as following?

1, vpoor
10, poor
6, average
11, good
12, vgood
13, good

Nick · Accepted Answer · 2018-12-07 05:38:34Z

4

The elements of $_SESSION['survey_ans'] are arrays, so you need to iterate through the values in each array to get your desired output. Try this:

foreach($_SESSION['survey_ans'] as $result) {
    foreach ($result as $key => $value) {
        echo $key."-".$value."<br />";
    }
}

Output:

1-vpoor
10-poor
6-average
11-good
12-vgood
13-good

Demo on 3v4l.org

edited Dec 7, 2018 at 5:38

answered Dec 7, 2018 at 5:26

Nick

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4 Comments

chancj Over a year ago

When i put 0 and i got the following error?Notice : Undefined offset: 0

Sean Over a year ago

why would it be $value[0], when they are [1]=> string(5) ...,[10]=> string(4) ..., [6]=> string(7) ..., etc?

chancj Over a year ago

I got the result as below but not the expected one??0-vpoor 1-poor 2-average 3-good 4-vgood 5-good

chancj Over a year ago

thanks for everyone for the valuable knowledge to me.

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