php run command in loop

Question

I want to run specific command 4 times in a loop. How do i do that?

$list = array(
"data1", "data2", "data3", "data4", "data5", "data6", "data7", "data8", "data9", "data10", "data11", "data12", "data13", "data14", "data15", "data17"
);

$split_by = 4;
$total_execute = round(count($list)/$split_by);
for($i=0; $i<=count($list); $i++)
{
//1
//2
//3
//4 //execute command 1
//5
//6
//7
//8 //execute command 2
//9
//10
..............

}

How can i execute command in every 4 index and total $total_execute time in php? I have tried but its not working. i have no idea.

okay edited. could you answer? I mean how do i execute $total_execute execute times only? — decoded
– decoded, Commented Dec 8, 2018 at 11:04

DinoCoderSaurus · Accepted Answer · 2018-12-08 11:12:28Z

1

If you only want to process every fourth item in the list, you can construct the loop to do that. (NB the fourth item is index 3).

for ($i=3; $i<count($list);$i+=4) {
//command
}

answered Dec 8, 2018 at 11:12

DinoCoderSaurus

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Comments

Ruks · Accepted Answer · 2018-12-08 11:19:35Z

0

The for-loop should be:

for($i = $split_by - 1; $i < count($list); $i += $split_by)
{
    for ($j = 0; $j < $total_execute; j++) {
        $elem = $list[$i];
        // Do something with '$elem'...
    }
}

edited Dec 8, 2018 at 11:19

answered Dec 8, 2018 at 11:08

Ruks

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