Bash function with only variables

Question

I have two functions that only store variables. Example:

Function datanode1(){
    homedirectory = "/path/to/file"
    ConfigDirectory = "/path/to/file"
    user = "john"
    max_open_Files = 262114
}

datanode2 is exactly the same, just different path files.

I would like to do something like this:

if [ "$a1" == "all" ]; then
    for i in [datanode2, datanode1] do
        *execute Script*
    done
fi

Is this possible? How are the functions acting as arrays?

Not Function, but function. and not both function and (). Just use datanote1() { ...; } — glenn jackman
– glenn jackman, Commented Dec 13, 2018 at 22:25
And not var = value but var=value -- see Shell Parameters and Simple Command Expansion — glenn jackman
– glenn jackman, Commented Dec 13, 2018 at 22:28

janos · Accepted Answer · 2018-12-13 21:36:43Z

2

If you have functions named datanode2 and datanode1, and you want to execute them in a loop, you could write like this:

for fun in datanode2 datanode1; do
    "$fun"
done

Btw the function definition in your example has some syntax error. It should be more like this:

datanode1() {
    homedirectory="/path/to/file"
    ConfigDirectory="/path/to/file"
    user="john"
    max_open_Files=262114
}

answered Dec 13, 2018 at 21:36

janos

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