Let's say I create object like this:
updates.push({
id: this.ids[i],
point: point,
value: value
});
Later on I want to use JSON.stringify on updates object, however I need only
point and value like:
updates[{point: 1, value: 12}, {point: 2, value: 24}]
What's the best ES6 solution for that?
I looked at some examples with delete, but that's not what I actually need, as I do not want to delete ids.
Try the following :
JSON.stringify(updates.map(({point,value})=>({point,value})));
let updates = [{id : 1, point : 1, value: 2},{id : 1, point : 1, value: 2}];
console.log(JSON.stringify(updates.map(({point,value})=>({point,value}))));If updates is an array. Then you might want something like this:
const newArrayWithoutId = updates.map(({ point, value }) => {
return {
point,
value,
}
}
({id, ...rest}) => ({...rest}) would be cleaner still.
updates items starts to contains more properties. You would get all of them, when possibly the OP just wants the point and value data points only.Just ({id, ...rest}) => ({...rest}) is too short for an answer, so how about this?
const withoutId = ({id, ...rest}) => ({...rest})
const vals = [
{id: 'a', point: 1, value: 'foo'},
{id: 'b', point: 2, value: 'bar'},
{id: 'c', point: 3, value: 'baz', meaning: 42}
]
const reduced = vals.map(withoutId)
console.log(reduced)
id". This is the only answer so far that has achieved that without hard-coding any property names. +1 from me - though this is all based on speculation unfortunately. OP will need to clarify.
JSON.stringify(value[, replacer[, space]]), leverage replacerpointandvalue, always? Or do you want every property except ID?