How to check with more RegEx for one address in python using re.findall()

Question

Ex: I want to apply the below regex rules

 # need to get address
    txt = "hello user 44 West 22nd Street, New York, NY 12345 from"    
    regexp = "[0-9]{1,3} .+, .+, [0-9]{5}"
    regexp1 = "[0-9]{1,3} .+, .+, [A-Z]{2} [0-9]{5}"
    regexp2 = "[0-9]{1,3} .+, .+, [A-Z]{2} [0-9]{9}"    
    re.findall(regexp, regexp1, regexp2, txt)

is this correct? I am getting error of this code

Are you sure that regular expressions are the appropriate tool for this job? — Lightness Races in Orbit
– Lightness Races in Orbit, Commented Dec 27, 2018 at 15:35
Perhaps more important, do any of those regex patterns even work on this input address string? — Tim Biegeleisen
– Tim Biegeleisen, Commented Dec 27, 2018 at 15:36
If you are getting error, then that's probably not correct. What is the error message? What do you expect? — Austin
– Austin, Commented Dec 27, 2018 at 15:36

Ragu Natarajan · Accepted Answer · 2018-12-28 05:50:42Z

2

Finally I got answer from here

How to combine multiple regex into single one in python?

Working fine this

import re
re1 = r'\d+\.\d*[L][-]\d*\s[A-Z]*[/]\d*'
re2 = '\d*[/]\d*[A-Z]*\d*\s[A-Z]*\d*[A-Z]*'
re3 = '[A-Z]*\d+[/]\d+[A-Z]\d+'
re4 = '\d+[/]\d+[A-Z]*\d+\s\d+[A-z]\s[A-Z]*'

sentences = [string1, string2, string3, string4]
generic_re = re.compile("(%s|%s|%s|%s)" % (re1, re2, re3, re4)).findall(sentence)

answered Dec 28, 2018 at 5:50

Ragu Natarajan

7393 silver badges16 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How to check with more RegEx for one address in python using re.findall()

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related