Replace string with a regex containing a variable without macro

Question

I need to delete some contents at the end of a string (eq_code) using Clojure. I want to implement a regex initialized by a variable (get-in vector [3 1]).

Maybe macro would have helped me.

Here is the code :

(reset! atom_code (clojure.string/replace eq_code #(str (get-in vector [3 1])) ""))

The error is :

IllegalArgumentException Invalid match arg: project.core$interpreted_lang_while$fn__4457@7ac4b7c5  clojure.string/replace (string.clj:102)

Is there a way to replace a substring without using macro ? For example using a function that return a regex.

Your code there passes an anon-function #(str ...) to str/replace. — cfrick
– cfrick, Commented Dec 30, 2018 at 9:28

leetwinski · Accepted Answer · 2018-12-29 11:47:25Z

3

https://clojuredocs.org/clojure.string/replace

replace match parameter (second arg) can't be a function. The solution is to construct the pattern from your dynamic value:

user> (def data [["a" "b"] ["c" "d"]])
#'user/data

user> (clojure.string/replace "mama" (re-pattern (get-in data [0 0])) "")
"mm"

and also: vector is the core function, so try not to shadow it by using it as a var name (though it's not actually what is wrong with your solution)

answered Dec 29, 2018 at 11:47

leetwinski

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1 Comment

Ilan Over a year ago

That is what I was looking for. Thanks

Alan Thompson · Accepted Answer · 2018-12-28 16:56:50Z

0

I think the problem is that vector is a clojure function, and I am guessing that you have some data named vector that is causing the compiler confusion.

Could you please update your question with sample data and desired output?

answered Dec 28, 2018 at 16:56

Alan Thompson

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1 Comment

Ilan Over a year ago

Finally, I have found a workaround to my problem. I no longer need using (string/replace). Thanks you for your help.

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