How to input char array in c++ in a single line?

Question

I just encountered an input statement for char array in c++ and I didn't understand how it works.

char s[100];
cin >> s + 1;
cout << s + 1;

Input : Harold

Output: Harold

Can anyone explain to me how it works?

It works exactly like any other char array. Sorry we don't know how much of C++ you know, so it's a bit difficult to pick a starting point for an explanation. Why exactly are you confused about these lines? — n. m. could be an AI
– n. m. could be an AI, Commented Dec 28, 2018 at 18:58
Make these changes char s[100] = "a"; Now at the end add cout << '\n' << s << '\n'; With that, can you tell what is going on? — David C. Rankin
– David C. Rankin, Commented Dec 28, 2018 at 22:02
@n.m. I was wondering how it works. We used to use loops to input an array but didn't know about this. Now I get this. Thanks a lot — Bhashkar Pandit
– Bhashkar Pandit, Commented Dec 30, 2018 at 6:40

smac89 · Accepted Answer · 2018-12-28 22:28:41Z

1

When you give the input 'Harold', the indices from 1 to 6 (As you do with s+1) will be assigned with the given characters. Other indices still contain garbages. This array looks like this: {'X','H','a','r','o','l','d','X','X',........} (Here 'X' means garbage)

But the thing is that when you want to get this array as output from s+1 (literally s[1]), It shows only the value you have assigned. Hence the output 'Harold'.

edited Dec 28, 2018 at 22:28

smac89

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answered Dec 28, 2018 at 22:24

Muhimin_Osim

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