Numpy array with repeating pattern

Question

How do you create a 1 x n array in NumPy following an incrementing pattern?

For example:

[0, 5, 10, 15, ... (n-1)*5]

Should your example output be [0, 5, 10, 15, ... (n-1)*5]? What you currently have doesn't make complete sense. — tel
– tel, Commented Dec 28, 2018 at 21:05

tel · Accepted Answer · 2018-12-28 22:56:25Z

1

np.arange is the correct answer (as pointed out in the comments). For completeness, here's a list of simple 1-liners that will produce the desired array:

np.arange(n)*5
np.arange(0, n*5, 5)
np.linspace(0, (n-1)*5, n, dtype=int)
np.array(range(0, n*5, 5))

For example, if n=7 then all of the above will produce the array:

[ 0  5 10 15 20 25 30]

edited Dec 28, 2018 at 22:56

answered Dec 28, 2018 at 21:08

tel

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