Java String to Date Convertion

Question

I'm trying to convert a string to date

I tried in couple ways but i'm getting the same.Please could any one help me out.

String stringDate ="20181228184821";
Date date = null;
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyyMMdd HH:mm:ss");
try {
    date = sdf1.parse(stringDate);
    System.out.println(date);
} catch (ParseException e) {
    System.out.println("ICICIBusinessLogic Error in converting input date string ****" + e);
}

I get the following exception :

Error in converting input date string ****java.text.ParseException: Unparseable date: "20181228184821"

Your format requires a space and two colons. The value you're trying to parse has none of those. — Makoto
– Makoto, Commented Dec 31, 2018 at 5:25
Date you are providing is unacceptable format "20181228184821" like 2018-12-28 18:48:21 — Kandy
– Kandy, Commented Dec 31, 2018 at 5:28
Thanks for the response but i'm getting the date String from the service with above mentioned format. — gopi kamatam
– gopi kamatam, Commented Dec 31, 2018 at 5:31
use SimpleDateFormat sdf1 = new SimpleDateFormat("yyyyMMddHHmmss") — DEVAS
– DEVAS, Commented Dec 31, 2018 at 5:37
I recommend you avoid the SimpleDateFormat class. It is not only long outdated, it is also notoriously troublesome. Today we have so much better in java.time, the modern Java date and time API. — Anonymous
– Anonymous, Commented Dec 31, 2018 at 7:54

Mohamed Anees A · Accepted Answer · 2018-12-31 05:27:14Z

2

Your stringDate should exactly match your format.

20181228184821 => 20181228 18:48:21 should work.

Or change your format to yyyyMMddHHmmss

answered Dec 31, 2018 at 5:27

Mohamed Anees A

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Comments

Elliott Frisch · Accepted Answer · 2018-12-31 05:31:07Z

1

You should use DateTimeFormatter and the new classes in java.time instead of the old SimpleDateFormat api. That being said, you appear to have confused your input and your output formats.

String fmtIn = "yyyyMMddHHmmss", fmtOut = "yyyyMMdd HH:mm:ss";
String stringDate = "20181228184821";
TemporalAccessor dt = DateTimeFormatter.ofPattern(fmtIn).parse(stringDate);
System.out.println(LocalDateTime.from(dt));
System.out.println(DateTimeFormatter.ofPattern(fmtOut).format(dt));

answered Dec 31, 2018 at 5:31

Elliott Frisch

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3 Comments

atheesh_27 Over a year ago

Is there any considerable issues of using SimpleDateFormat compared to DateTimeFormatter?

Anonymous Over a year ago

@AtheeshRathnaweera There are too many to mention here. SimpleDateFormat is causing a lot of trouble for many programmers, and its fellows like Date are poorly designed too.

Anonymous Over a year ago

@ElliottFrisch Going through a TemporalAccessor is not the recommended way. Just do LocalDateTime dt = LocalDateTime.parse(stringDate, DateTimeFormatter.ofPattern(fmtIn)); (and drop the from call in the following line). Thanks for showing the use of the modern API.

Nicholas K · Accepted Answer · 2018-12-31 13:05:28Z

1

You are using the wrong pattern, use the following instead :

SimpleDateFormat sdf1 = new SimpleDateFormat("yyyyMMddHHmmss");

Also, SimpleDateFormat is long outdated, make use of java-8's java.time

LocalDateTime.parse(stringDate, DateTimeFormatter.ofPattern("yyyyMMddHHmmss"));

edited Dec 31, 2018 at 13:05

answered Dec 31, 2018 at 5:26

Nicholas K

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Comments

prophet1906 · Accepted Answer · 2018-12-31 06:06:06Z

0

The pattern specified in Simple Date Format Constructor should be same as the string to be parsed.

Try String stringDate ="20181228 18:48:21";

answered Dec 31, 2018 at 6:06

prophet1906

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