Using "string.byte" on a UTF-8 character returns an array, how can I convert that array back to the UTF-8 character?

Question

Let me explain my issue with an example:

local Character = utf8.char(1114111) --Example UTF8 character
local A,B,C,D = Character:byte(1, -1)
print(A,B,C,D) -- 244 143 191 191

How can I convert "244 143 191 191" back to "1114111"?

utf8.codepoint(string.char(table.unpack{A, B, C, D}))

Egor Skriptunoff
– Egor Skriptunoff

2018-12-31 11:46:31 +00:00
Commented Dec 31, 2018 at 11:46 — Egor Skriptunoff
– Egor Skriptunoff, Commented Dec 31, 2018 at 11:46
Thank you so much, it works just as I want it!

Aorda
– Aorda

2018-12-31 12:29:42 +00:00
Commented Dec 31, 2018 at 12:29 — Aorda
– Aorda, Commented Dec 31, 2018 at 12:29

Nicol Bolas · Accepted Answer · 2018-12-31 14:45:32Z

2

The utf8.codepoint function takes a byte array as a string and converts it into a sequence of codepoints, with each return value being a separate codepoint. So you just have to convert those four values into a string for use by utf8.codepoint. string.char(A, B, C, D) would do it adequately.

answered Dec 31, 2018 at 14:45

Nicol Bolas

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