Send file CURL + PHP 7

Question

I use code for send zip file and this work good:

$file = ''.$_SERVER['DOCUMENT_ROOT'].'/projects/file.zip';
$data = array(
    "file" => new CURLFile($file),
    "data" => '{"title":"Test"}'
);
$handle = curl_init();
curl_setopt($handle, CURLOPT_URL, 'https://example.com');
curl_setopt($handle, CURLOPT_RETURNTRANSFER, true);
curl_setopt($handle, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($handle, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($handle, CURLOPT_HTTPHEADER, array(
  'Content-type: multipart/form-data;',
));
curl_setopt($handle, CURLOPT_POSTFIELDS, $data);
$final = curl_exec($handle);
$response = json_decode($final, true);
curl_close ($handle);

But when I send a file with the .keystore extension, nothing works. I do not receive errors on the server.

How do I properly send such a file?

The filename (including extension) or even content of a file shouldn't make any difference to how you send it; all CURLFile is doing is reading the contents of the file and transmitting it in a suitable encoding. — IMSoP
– IMSoP, Commented Jan 4, 2019 at 12:17
You're right. I spent a lot of time. The error was in the file path.) — Anton Bogomolov
– Anton Bogomolov, Commented Jan 4, 2019 at 12:22

sen · Accepted Answer · 2019-01-04 13:25:21Z

2

you can try this

$file = ''.$_SERVER['DOCUMENT_ROOT'].'/projects/file.zip';
$mime = mime_content_type($file);
$info = pathinfo($file);
$name = $info['basename'];
$output = new CURLFile($file, $mime, $name);

$data = array(
    "file" => $output,
    "data" => '{"title":"Test"}'
);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'https://example.com');
curl_setopt($ch, CURLOPT_POST,1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
$result = curl_exec($ch);
if (curl_errno($ch)) {
   $result = curl_error($ch);
}
curl_close ($ch);

answered Jan 4, 2019 at 13:25

sen

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