I have this string :
Item 1Item 2Item 3Item 4
I want to get :
["Item 1", "Item 2", "Item 3", "Item 4"]
I tried to do this :
var string = 'Item 1Item 2Item 3Item 4'
var regex = string.split(/(\d)/)
regex.splice(-1, 1)
regex[regex.length - 2] += regex[regex.length - 1];
regex.splice(-1, 1)
console.log(regex);But it doesn't work, any idea how to get the desired result?
EDIT :
The string at max could look like this :
Item 1Item 2Item 3Item 4Item NItem N-1
Note: the answer handles the original case - before the update
Use String.match() to find a sequence of non numbers that ends with a sequence of numbers (regex101):
var string = 'Item 1Item 2Item 3Item 4'
var arr = string.match(/\D+\d+/g)
console.log(arr);
\d -> \d+ is better
Item 1Item 2Item 3Item 4Item NItem N-1?
"Item N" or "Item N-1" in your string, or is "N" and "N-1" just a placeholder for an arbitrary sequence of digits. (You need to use very precise language when discussing regexes).Item NItem N-1, and they're not numbers ^^ So can I use /\D+|N+|N\-1+/g?When you have a capturing group ((...)) in the regex you pass to .split, the captured text is returned as part of the result. This is why you have the "1", "2", etc. in between the "Item "'s.
Apart from some variation of @Ori Dori's solution, you could also solve this with a lookahead assertion (?=...), which is a non-capturing construct.
var string = 'Item 1Item 2Item 3Item 4Item NItem N-1';
var arr = string.split(/(?=Item)/);
console.log(arr);This will work by breaking apart the string immediately before any appearance of the text "Item".
For a more brute-force solution without using regex at all:
var string = 'Item 1Item 2Item 3Item 4Item NItem N-1';
var arr = [];
var i = string.indexOf('Item', 1);
while (i >= 0) {
arr.push(string.substr(0, i));
string = string.substr(i);
i = string.indexOf('Item', 1);
}
arr.push(string);
console.log(arr);If your elements always start with the word Item you can do something like this using split():
const str = 'Item 1Item 2Item 3Item 4Item N-2Item N-1Item N'
var arr = str.split("I").slice(1).map(x => "I" + x);
console.log(arr);Even better, and alternatively you can do it with a single regular expression using match()
const str = 'Item 1Item 2Item 3Item 4Item 999Item N-2Item N-1Item N'
var arr = str.match(/Item\s[1-9|N|-]+/g);
console.log(arr);To achieve expected result, use below option with replace, split and slice
var str = "Item 1Item 2Item 3Item 4Item NItem N-1"
let arr = str.replace(/\I/g, ' I').split(' ').slice(1);
console.log(arr)codepen - https://codepen.io/nagasai/pen/qLzKwJ?editors=1010
But I rather got :as inBut I'd rather get:?string.split(/(?!^)(?=Item)/)