WPF Listview GridView Binding: Dynamic Columns

Question

I am binding a DataGrid to a DataSet on my ViewModel.

I would like to switch to a more light weight control such as ListView.GridView, but it doesn't appear it supports dynamic column generation.

Since this is a MVVM model, i am trying to avoid having to loop through my dataset columns, and add each GridViewColumn from a codebehind.

is it possible to 1. Bind ad a Listview to a DataSet w/out setting columns explicitly, or 2. Bind the Columns collection to a property on the ViewModel.

If not, what are some other free grid controls that would allow this and outperform DataGrid?

so the DataSet is not strongly-typed? so it is dynamic?

Robbie Tapping
– Robbie Tapping

2011-03-24 23:55:30 +00:00
Commented Mar 24, 2011 at 23:55 — Robbie Tapping
– Robbie Tapping, Commented Mar 24, 2011 at 23:55
that is correct. Not strongly typed

Sonic Soul
– Sonic Soul

2011-03-24 23:56:50 +00:00
Commented Mar 24, 2011 at 23:56 — Sonic Soul
– Sonic Soul, Commented Mar 24, 2011 at 23:56

Robbie Tapping · Accepted Answer · 2011-03-25 00:07:14Z

0

Dont believe you can do it easily, i would personally use the IValueConverter interface to convert your DataSet to an object that you can manage your columns inside.

public sealed class DataSetConverter : IValueConverter
    {

        #region IValueConverter Members

        public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
        {
           if((DataSet)value != null)
{

// Put logic in here to loop through the columns and create an object to bind to the ListView control.

}
        }

        public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
        {
            throw new NotImplementedException();
        }

        #endregion
    }

XAML Code

 <conv:DataSetConverter x:key="datasetConverter"/>
                <ListBox x:Name="listbox1" ScrollViewer.HorizontalScrollBarVisibility="Disabled" 
                        ItemsSource="{Binding datasetObject, Converter={StaticResource datasetConverter}}" >

answered Mar 25, 2011 at 0:07

Robbie Tapping

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3 Comments

Sonic Soul Over a year ago

do you know why DataGrid does it transparently but not Gridview?

Robbie Tapping Over a year ago

a Gridview does do it, just make sure that you switch on the AutoGenerateColumns=true

Sonic Soul Over a year ago

yes i tried that. Same property is necessary for DataGrid to generate columns . GridView does not do it

ScottGardner · Accepted Answer · 2011-03-25 19:20:20Z

Assume DataSet1:

Customer
  Name
  Address
  Phone

Model:

namespace WpfApplication1.Model
{
    class MyDataSetModel
    {
        private DataSet1 _myDataSet;
        private DataSet1TableAdapters.CustomerTableAdapter _myCustomerTableAdapter;
        public DataSet1.CustomerDataTable Customers
        {
            get { return _myDataSet.Customer; }   
        }

        public void FetchCustomers()
        {
            _myDataSet = new DataSet1();
            _myCustomerTableAdapter = new CustomerTableAdapter();
            _myCustomerTableAdapter.Fill(_myDataSet.Customer);
        }
    }
}

ViewModel: (combined with View here for clairity)

public partial class Window1 : Window
{
    private MyDataSetModel _myDataModel;
    public Window1()
    {
        InitializeComponent();
        Loaded += new RoutedEventHandler(Window1_Loaded);
    }

    void Window1_Loaded(object sender, RoutedEventArgs e)
    {
        _myDataModel = new MyDataSetModel();
        _myDataModel.FetchCustomers();

        listView1.ItemsSource = _myDataModel.Customers;
    }
}

View:

<Window x:Class="WpfApplication1.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="400" Width="600">
    <Grid>
        <ListView Name="listView1">
            <ListView.View>
                <GridView>
                    <GridViewColumn DisplayMemberBinding= "{Binding Path=Name}">
                        <GridViewColumnHeader Width="100">Name</GridViewColumnHeader>
                    </GridViewColumn>

                    <GridViewColumn DisplayMemberBinding= "{Binding Path=Address}">
                        <GridViewColumnHeader Width="340">Address</GridViewColumnHeader>
                    </GridViewColumn>

                    <GridViewColumn DisplayMemberBinding= "{Binding Path=Phone}">
                        <GridViewColumnHeader Width="100">Phone</GridViewColumnHeader>
                    </GridViewColumn>
                </GridView>
            </ListView.View>
        </ListView>
    </Grid>
</Window>

He asks about dynamic column generation but not about knowingly column set. You just described a common use case. Next time please read the question carefully.

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