When I am trying to determine if an empty array is greater than 0, but returns true. why php empty array greater than 0 ?
$a = [];
if (is_array($a) && count($a) > 0) {
die('array');
} elseif ($a > 0) {
die('ok');
}
it's output 'ok', Can anyone tell me why this is?
http://php.net/manual/en/language.operators.comparison.php According to php documentation, when comparing array against any other type other than array the array is always considered greater. It is just how the comparison is defined. My guess is that when comparing two variables which could be of any type, the comparison rule enforces array to be unequal to any other type.
Consider using empty() to check for an empty array, I am of the impression that it does not need to perform the work needed to discover the count to only determine if the array is empty and should be a faster result.
To demonstrate in your scenario ( including the array check, though you should trust it as an array as you're strictly defining it as one but I can understand you are just providing an example and it might be from an unknown source )
$a = [];
if (is_array($a)) {
die(empty($a) ? 'empty' : 'not empty');
} else {
die('Not an array');
}
Thanks @Quasimodo's clone @u_mulder
if ($a)will work just fine.